Differences
This shows you the differences between two versions of the page.
| Both sides previous revisionPrevious revision | |||
| courses:cs211:winter2011:journals:chen:chapter_3 [2011/02/02 05:16] โ [3.4 Testing Bipartiteness: An Application of Breadth-First Search] zhongc | courses:cs211:winter2011:journals:chen:chapter_3 [2011/02/16 12:33] (current) โ zhongc | ||
|---|---|---|---|
| Line 69: | Line 69: | ||
| Interesting/ | Interesting/ | ||
| + | |||
| + | |||
| + | ====== 3.6 Directed Acyclic Graphs and Topological Ordering ====== | ||
| + | definitions: | ||
| + | * If a directed graph has no cycles, we call it--naturally enough--a directed acycIic graph, or a DAG. | ||
| + | * analogous to any dependant systems in problem solving | ||
| + | * DAGs can be used to encode precedence relations or dependencies in a natural way. | ||
| + | |||
| + | Problem: | ||
| + | Goal: Find an algorithm for finding the TO. | ||
| + | We can represent such an interdependent Set of tasks by introducing a node for each task, and a directed edge (i, j) whenever i must be done before j. The graph must be a DAG. | ||
| + | |||
| + | Preparation: | ||
| + | G has a topological ordering, then G is a DAG. | ||
| + | proof: | ||
| + | contradiction, | ||
| + | then see what happens to the max indexed nodes...see p126. | ||
| + | |||
| + | In every DAG G, there is a node v with no incoming edges. | ||
| + | proof: | ||
| + | same idea as above. | ||
| + | |||
| + | |||
| + | Algo Idea: | ||
| + | find a node v with no incoming edges | ||
| + | Order v first | ||
| + | Delete v from G | ||
| + | Recursively compute a topological ordering of G-{v} | ||
| + | and append this order after v. | ||
| + | |||
| + | |||
| + | |||
| + | Readable/ | ||
