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--- courses:cs211:winter2018:journals:holmesr:section_3.1 [2018/02/06 03:56] – [Section 3.4 Testing Bipartiteness: an Application of BFS] holmesr
+++ courses:cs211:winter2018:journals:holmesr:section_3.1 [2018/02/06 04:53] (current) – holmesr
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 This section was fascinating in that it demonstrated that determining bipartiteness of a graph is reliant on the same algorithmic skeleton as the BFS algorithm.
+===== Section 3.5 Connectivity in Directed Graphs =====
+First, directed graphs require two adjacency lists in order to be properly represented since an edge may go from node //u// to node //v// but not return from //v// to //u//. One lists represents the edges that leave a node and the nodes that those edges connect to, and the other list represents the edges which lead to a node and from which node they come. They are called the //from list// and the //to list//, respectively.
+The graph search algorithms BFS and DFS perform almost the same with directed graphs as they do with undirected graphs. The major difference being that they use a node's //from list// to traverse through the nodes which the current node has an edge from itself to them. It is important to note that in a directed graph, a node //n// can have a path to node //r//, but node //r// is not required to have a path back to node //n//. The graph traversals are discovering nodes to which //n// has a path; these paths are not necessarily reciprocated.
+It is interesting that these traversals are finding all the nodes to which  node //n// has a path, but to find all the nodes with paths to //n//, the same traversal can be run on an identical graph with the directions of the edges reversed. This leads into a discussion of strong connectivity and mutual reachability.
+A graph is strongly connected if all nodes u and v which have paths (u,v) also have paths (v,u). In other words, if all nodes are mutually reachable to one another. An interesting property of mutual reachability is that if two nodes are mutually reachable and a third node is mutually reachable to one of those two, then it is mutually reachable to the other also.
+The strong component is an analog to the connected component in an undirected graph. The strong component in a graph G is the set of nodes //n// which are mutually reachable from the nodes //s//. The a set of nodes is a strong component if that set is returned by a BFS started at node //n// on graph G and also returned by a BFS started at node //n// on a graph G<sup>rev</sup> (the graph G with the directions of the edges reversed.) The strong component also has an analogous property to the connected component of undirected graphs that it is identical or disjoint for two nodes.
+===== Section 3.6 DAGS and Topological Orderings  =====
+A Directed Acyclic Graph (DAG) is just what it sounds like, a directed graph containing no cycles. These are useful for representing precedence relations and dependencies because they don't contain cycles. A cycle in a dependency relation would mean that one process could not start until another had taken place, which would never happen because none could start first.
+These types of graphs have can also be represented by a structure known as a topological ordering, which the book defines as "an ordering of the nodes v<sub>1</sub>,...,v<sub>n</sub> such that for every edge (v<sub>i</sub>,v<sub>j</sub>), i<j". Every topological ordering represents a DAG since a topological ordering must have directed edges of course, and these edges can not be in a cycle because eventually that would violate the condition that for every edge (v<sub>i</sub>,v<sub>j</sub>), i<j.
+It is also true that every DAG has a topological ordering, since there must be a node that has no incoming edges due to the fact that there are no cycles in a DAG. Once this node has been removed and removing a node cannot create a cycle, then there is a DAG remaining with all the nodes that were in the previous DAG, except the removed node. This truth can be used to devise an algorithm that runs in O(n<sup>2</sup>) time:
+.find the node with no incoming edges
+.delete this node
+.recursively compute the topological ordering of the DAG without the removed node and add this after the deleted node.
+There is yet a faster, linear-time method to computing the topological ordering of the DAG, but I could not quite grasp what this was. It dealt with active nodes and edges coming from those nodes into the current node.